Integralai, reikia pagalbos

Sveiki, gal galite padėti su šiais dviem integralais?

[tex]\int (5-2x)^{10}\;dx=-\frac{1}{2}\int (5-2x)^{10}\;d(5-2x)=-\frac{(5-2x)^{11}}{22}+C[/tex]
[tex]\int \frac{dx}{x(16+\ln^2{x})}=\int \frac{d(\ln{x})}{(16+\ln^2{x})}=\frac{1}{4}\int \frac{d(\frac{\ln{x}}{4})}{(1+(\frac{\ln{x}}{4})^2)}=\frac{1}{4}\arctan(\frac{\ln{x}}{4})+C[/tex]