limai

[tex]\lim_{x\to\0} \frac{12x-\arctan12x}{tgx-sinx}[/tex]

gal galetumet padet issprest? :)

o koki buda taikete? :)

o kaip toki uzdavini liopitalio taisykle issprest?

teiloro formulė ten.

[tex]\lim_{x\to\frac{pi}{2}} (cos(4x))^{tg^{2}(3x)}[/tex]

o kokiu budu toki issprest? :)

Kai skaicius laipsnyje pavyzdzius radau tik kai neapibreztumas 1∞ , o cia gaunasi neapibreztumas [tex]({\frac{0}{0}){^{x+1}}[/tex] 

Kaip ispresti?

[tex]\left(\frac{\cancel{x-1}}{\cancel{(x-1)}(x+1)}\right)^{x+1}=\left(\frac12\right)^2=\frac14[/tex]

Aciu aciu labai Tau ! .
Bet eina sau :D , cia toks sprendimas, o as ieskau kosmosu kazkokiu :D

Kaip sita ispresti su lopitalio? As bandau man nesigauna :/ .