Entogula +59
[tex]log_{2}x-log_{64}x=2\frac{1}{2}[/tex]
Galiu susivienodinti pagrindus.
[tex]log_{2}x-log_{2^{6}}x = 2\frac{1}{2}[/tex]
[tex]log_{2}x-log_{2}x^{\frac{1}{6}} = 2\frac{1}{2}[/tex]
[tex]log_{2}\frac{x}{x^{\frac{1}{6}}} = 2\frac{1}{2}[/tex]
[tex]\left (2\frac{1}{2} \right )^{2}=\frac{x}{x^{\frac{1}{6}}}[/tex]
Ką toliau daryti?