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Reiškinio suprastinimas


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vardiklis tik x ar x-3?

Taksas027vardiklis tik x ar x-3?


x-3

[tex]\[\begin{array}{l}
\frac{{x + 2\sqrt {3x}  + 3}}{{x - 3}}\\
\frac{{x + 2\sqrt {3x}  + 3}}{{{{\left( {\sqrt x } \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}}}
\end{array}\][/tex]

[tex]\[\frac{{{{(\sqrt x  + \sqrt 3 )}^2}}}{{{{\left( {\sqrt x } \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}}}\][/tex]

[tex]\[\begin{array}{l}
\frac{{{{(\sqrt x  + \sqrt 3 )}^2}}}{{(\sqrt x  + \sqrt 3 )(\sqrt x  - \sqrt 3 )}}\\
\frac{{\sqrt x  + \sqrt 3 }}{{\sqrt x  - \sqrt 3 }}
\end{array}\][/tex]

variable[tex]\[\begin{array}{l}
\frac{{x + 2\sqrt {3x}  + 3}}{{x - 3}}\\
\frac{{x + 2\sqrt {3x}  + 3}}{{{{\left( {\sqrt x } \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}}}
\end{array}\][/tex]

[tex]\[\frac{{{{(\sqrt x  + \sqrt 3 )}^2}}}{{{{\left( {\sqrt x } \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}}}\][/tex]

[tex]\[\begin{array}{l}
\frac{{{{(\sqrt x  + \sqrt 3 )}^2}}}{{(\sqrt x  + \sqrt 3 )(\sqrt x  - \sqrt 3 )}}\\
\frac{{\sqrt x  + \sqrt 3 }}{{\sqrt x  - \sqrt 3 }}
\end{array}\][/tex]

Esu dėkinga jums labai. :)

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